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When we use cin >> x as a condition, we aren't just testing the condition; we are also reading a value into x as a side effect Now, all we need to do is figure out what it means to use cin as a condition in a while statement Because cin has type istream, which is part of the standard library, we must look to the definition of istream for the meaning of if (cin) or while (cin) The details of that definition turn out to be complicated enough that we won't discuss it in detail until 125/222 However, even without these details, we can already understand a useful amount of what is happening The conditions that we used in 2 all involved relational operators that directly yield values of type bool In addition, we can use expressions that yield values of arithmetic type as conditions When used in a condition, the arithmetic value is converted to a bool: Nonzero values convert to true; zero values convert to false For now, what we need to know is that similarly, the istream class provides a conversion that can be used to convert cin into a alue that can be used in a condition We don't yet know what type that value has, but we do know that the value can be converted to bool Accordingly, we know that the value can be used in a condition The value that this conversion yields depends on the internal state of the istream object, which will remember whether the last attempt to read worked Thus, using cin as a condition is equivalent to testing whether the last attempt to read from cin was successful There are several ways in which trying to read from a stream can be unsuccessful: We might have reached the end of the input file We might have encountered input that is incompatible with the type of the variable that we are trying to read, such as might happen if we try to read an int and find something that isn't a number.

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barcode encoder on java using barcode encoder for Note, as mentioned above, that the trial wave functions hich contain integrals that require numerical evaluation, ie the 2D and the variable symmetry case which contain the integrals between 0 and 1 with respect to w, demand around eight wave function points per A for complete convergence The data displayed earlier in Fig 510 as a comparison between the 2D and the 3D case, was obtained quickly with the standard mesh of 1 point per A, ie 6z = 1 A This was acceptable at that point in order to illustrate merely that the 3D case gave lower variational energies than the 2D case However, for the purposes of demonstrating that the variable symmetry case gives lower energies still, more accurate calculations were necessary, and indeed for Table 51, 6z in the iterative equation (equation (5.

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28)) was required to be 01 A The disadvantage to moving to such accuracy is, of course, the increased computational effort, which is roughly inversely proportional to 6z; hence an increase by a factor of 10 in the number of wave function points leads to a similar increase in computational time Table 51 clearly illustrates that the variable symmetry trial function gives the lowest energies, for all donor positions, although in terms of energy the 3D wave function is a very good approximation also, with energies differing by less than 01 meV In comparison with the more accurate evaluation of the energy for the 2D case, this differs by up to 07 meV Figures 518 and 519 illustrate the results of detailed calculations for the GaAs/ Ga 1 _ x Al x As system The energies in Fig 5.

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18 are similar in form to those obtained earlier, with the interest here lying with the symmetry of the wave function, as given in Fig 519 Most obviously, it is clear that the values of C imply that the donor wave function will assume symmetries that are neither 2D or 3D, thus justifying the investment in the variable symmetry analysis The value of C is non-monotonic as a function of donor position, with a local minimum for donors at the centre of the well and a peak for donors near the well-barrier interface; this is the exact same behaviour as reported by Roberts et al [108] for the CdTe-Cd1 xMnxTe system and hence appears to be a generic result Typically, it is found that C ~ 07, and hence the variable-symmetry trial wave function looks like the following: contain integrals that require numerical evaluation, ie the .

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