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years of foreign language Michigan required, but she was so impressed by his grades and his new-found passion for attending the school that she made an exception and admitted him for the fall term Miss Buntin could never know that her simple decision would eventually reap the university millions in gifts from the Walgreen family, which would send three generations (and counting) to the campus The donations have helped Michigan s College of Pharmacy retain its place among the nation s elite In fairness, there was no way Miss Buntin could have guessed, because Chuck decided to enroll in the school s college of architecture So, she told me, be sure to study well, Chuck recalled My first blue book exam, I thought the whole thing was a big mistake, because the professors asked questions about the beginning of the subject, which I d never learned, and I didn t think that was a very nice thing to do All I did was play poker, instead of review I didn t do so well on the final exams two As and two Bs 40 Not bad, of course, but not nearly as impressive as the Apluses Chuck had earned at U-C high After I got the grades and my dad saw them, he said he knew I could do better, Chuck recalled Chuck, we have to talk seriously, he said If you think you d like to get into the drug business, there are a couple things you have to do, and one is pass the state board exam for pharmacology 41 Thanks to Prohibition, the rules had changed since Charles Sr worked as a clerk when he first arrived in Chicago To prevent pharmacies from selling alcohol under the guise of medicinal purposes, the State of Illinois mandated that all drugstores be run by state-licensed pharmacists, who risked losing their licenses if they made any backdoor prescriptions Chuck decided to take the year off school, work for his dad s company, and see if he liked it Despite being assigned to the rigorous store-opening team, Chuck liked the work just fine and decided to follow in his father s footsteps He returned to Michigan in the fall of 1926, this time as a student in the College of Pharmacy After graduating in 1928, he returned to Walgreens Chicago headquarters, where he met his future wife, Mary Ann Leslie.

(633)

a leg that was previously disconnected from the group, ie placed on hold An example is given in Figure 69 After leg 3 is moved to call segment 1, call segment 2 is released by the CSA Call segment 1 now contains three legs: one incoming leg and two outgoing legs These three legs are in speech connection with one another The signal sequence that is used to move the additional call party to the group is re ected in Figure 610 In the example sequence ow in Figure 610, the CAMEL service creates an additional party, leg 3, in a call When the newly created call party has answered the call, the CAMEL service uses the move leg operation to move leg 3 to call segment 1 Move leg is one of the CPH operations

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Clearly, (633) is true for m = 1 Suppose that (633) is true for m = n Substituting equations (632) into the right-hand side of (633) with m = n, it follows that

i =

where the latter equality involves an interchange of the order of summation Next, using (621), we get (633) for m = n + 1, which completes the induction step Using the relation (622) for the total expected costs over the rst m decision epochs, we can rewrite (633) in the more convenient form i = Vm (i, R) mg +

j I (m) pij (R) j ,

To additional called party 2 (active) To called party (active)

(634)

Since Vm (i, R)/m g(R) as m for each i, the result g = g(R) follows by dividing both sides of (634) by m and letting m To prove the second part of assertion (b), let {g, i } and {g , i } be any two solutions to (631) Since g = g = g(R), it follows from the representation (634) that i i =

.

j I (m) pij (R){ j j },

By summing both sides of this equation over m = 1, , n and then dividing by n, it follows after an interchange of the order of summation that i i = 1 n

To additional called party 1 (alerting)

n m=1 (m) pij (R) ( j j ),

j (R)( j j ),

The right-hand side of this equation does not depend on i This proves part (b) (c) Since j pij (Ri ) = 1 for each i I , it follows that for any constant c the numbers g and i = wi (R) + c, i I , satisfy (632) Hence the equations (632)

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